0=-16t^2+79t+6

Solution for 0=-16t^2+79t+6 equation:

0=-16t^2+79t+6

We move all terms to the left:

0-(-16t^2+79t+6)=0

We add all the numbers together, and all the variables

-(-16t^2+79t+6)=0

We get rid of parentheses

16t^2-79t-6=0

a = 16; b = -79; c = -6;
Δ = b2-4ac
Δ = -792-4·16·(-6)
Δ = 6625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6625}=\sqrt{25*265}=\sqrt{25}*\sqrt{265}=5\sqrt{265}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-5\sqrt{265}}{2*16}=\frac{79-5\sqrt{265}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+5\sqrt{265}}{2*16}=\frac{79+5\sqrt{265}}{32}
$